Respuesta :

[tex]\bf \begin{cases} c(x)=4x-2\\ d(x)=x^2+5x \end{cases}\qquad (c\circ d)(x)\iff c[\ d(x)\ ] \\\\\\ c[\ d(x)\ ]=4\boxed{d(x)}-2\implies c[\ d(x)\ ]=4\left( \boxed{x^2+5x} \right)-2 \\\\\\ c[\ d(x)\ ]=4x^2+20x-2[/tex]

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