Given the repeating decimal 0.48( 8 repeating)
[tex]\begin{gathered} \frac{44}{90}=\frac{22}{45}=0.4\bar{8} \\ \frac{66}{135}=\frac{22}{45}=0.4\bar{8} \\ \frac{48}{99}=0.\bar{48} \\ \frac{48}{100}=0.48 \end{gathered}[/tex]Therefore, A and B are equivalent to the repeating decimal.
