We can apply trigonometric ratios, on this case we ned to use sine
[tex]\sin (\alpha)=\frac{O}{H}[/tex]Where alpha is th reference angle, O the opposite side from the reference angles and H the hypotenuse of the triangle
On our case O is b and H is c, then replacing
[tex]\sin (B)=\frac{b}{c}[/tex]then sinB is b/c, then right option is first
