katieusc
katieusc
04-02-2017
Mathematics
contestada
I need to know how to solve for the value of x
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garydesir1
garydesir1
04-02-2017
Hey Katie
4^2x+3 = 1
We need to solve for x
log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
x = -3/2
I hope that's help !
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