[tex]\sf \boxed{\bold{k = 3}}[/tex]
Explanation:
If the first values of the two ordered pairs are the same, the relation is not a function.
Solve:
2k + 1 = 3k -2
2k - 3k = -2-1
-k = -3
k = 3
When k = 3, for the relation R= {(2k+1, 3), (3k-2, -6)} will not be a function.
