Answer:
Hey There!
Let's solve....
[tex]v = \frac{1}{2} k{x}^{2} \\ \\ \frac{ v_{1} }{ v_{2} } = (\frac{ x_{1} }{ x_{2}}) ^{2} \\ \\ \frac{v}{ v_{2} } =( \frac{ \cancel{2}}{ \cancel{10 }}) ^{2} \\ \\ = \frac{1}{25} \\ \\ v_{2} = 25v_{1} \\ \\ = 25v [/tex]
I hope it is helpful to you...
Cheers!_______
