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03-01-2017
Mathematics

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Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of
2 in each case.

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surjithayer surjithayer

03-01-2017

12=2*2*3
45=3*3*5
15=3*5
10=2*5
L.C.M=2*2*3*3*5=180
required number 180+2=182

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