Answer:
6733.5 g of NaCl
Explanation:
We can assume that the salt solution is a saline solution which contains NaCl in water at 0.90%, whose density is 1.005 g/ml.
So we need to apply the density concept to solve the question.
Density = mass / volume
We convert dL to mL → 67 dL . 100mL / 1 dL = 6700 mL
Density = mass / volume
Volume . Density = mass
6700 mL . 1.005 g = 6733.5 g of NaCl
