Answer:
112°
Step-by-step explanation:
By inscribed angle theorem:
[tex] m\widehat {BCD} = 2\times m\angle BAD\\
\therefore m\widehat {BCD} = 2\times 129\degree \\
\therefore m\widehat {BCD} = 258\degree\\\\
\because m\widehat{CD} = m\widehat {BCD}-m\widehat{BC} \\
\therefore m\widehat{CD} = 258\degree - 146\degree \\
\huge \red {\boxed {\therefore m\widehat{CD} = 112\degree}} [/tex]
