Respuesta :

Answer:

53.13

Step-by-step explanation:

mJKL = sin-1(9/15) = 36.9 deg

mKJL = = 36.9 deg ...base angles of isosceles triangle JKL

mJLK = 180 - 36.9 - 36.9 = 106.26 deg

mJPK = mJLK/2 = 106.29/2 = 53.1 deg......half of central angle

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