Answer:
341°
Step-by-step explanation:
[tex]m\angle DPC = m \angle APB = 19° \\ .. (Vertical\: \angle 's) \\
\therefore m(arc DC) = m\angle DPC= 19° \\
\because m(arc DBC) = 360°-m(arc DC) \\ \therefore \: m(arc \: DBC) = 360 \degree - 19 \degree \\ = 341 \degree \\ \red{ \boxed{ \bold{\therefore \: m(arc \: DBC)= 341 \degree}}} \\ [/tex]
