Answer:
Step-by-step explanation:
Let f(x) = x^7 - 4e^x .
Then f '(x) = 7x^6 - 4e^x, and
f "(x) = 42x^5 - 4e^x, and so:
f '(-1) = 7(-1)^6 - 4e^(-1) = 7 + 4/e
and
f "(x) = 42(-1)^5 - 4e^(-1) = -42 + 4/e
