Answer: [tex]\bold{\dfrac{3}{2}}[/tex]
Step-by-step explanation:
[tex]\dfrac{12z^2}{2y^2}\\\\\\y = -2\quad z=-1\\\dfrac{12(-1)^2}{2(-2)^2}=\dfrac{12(1)}{2(4)}=\dfrac{12}{8}\\\\\\\dfrac{12}{8}\div \dfrac{4}{4}=\boxed{\dfrac{3}{2}}[/tex]
