Respuesta :

gmany

[tex] (x^3-8x^2+19x-9)\div(x-4)=x^2-4x+3\\\underline{-x^3+4x^2}\\=-4x^2+19x\\\underline{\ \ \ \ \ 4x^2-16x}\\.\ \ \ =3x-9\\\underline{\ \ \ \ \ -3x+12}\\.\ \ \ \ \ =\ 3 [/tex]

[tex]x^3-8x^2+19x-9=(x^2-4x+3)(x-4)+3[/tex]